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help > RE: Design matrix
Dec 20, 2017 05:12 AM | Andrew Zalesky
RE: Design matrix
Hi Alex,
yes - this is correct. No exchange block is required in this case because it is not a repeated measures design.
The contrast will test for controls > patients
If you change the contrast to [-1 1], you will instead test controls < patients.
Andrew
Originally posted by Alexia Bourgeois:
yes - this is correct. No exchange block is required in this case because it is not a repeated measures design.
The contrast will test for controls > patients
If you change the contrast to [-1 1], you will instead test controls < patients.
Andrew
Originally posted by Alexia Bourgeois:
Hi Andrew,
Thanks a lot for your very helpful answer!
Just to be sure, for the 2nd design, if I would like to test Controls vs Patients at each time points, is the following matrix ok?
(C for control, P for patients, T for Time-point, here for two controls and 2 patients and for Time point 1).
C1T1 1 0
C2T1 1 0
P1T1 0 1
P2T1 0 1
Contrast: [1 -1]
No need to exchange blocks?
Thanks again,
Have a nice day,
Alexia
Thanks a lot for your very helpful answer!
Just to be sure, for the 2nd design, if I would like to test Controls vs Patients at each time points, is the following matrix ok?
(C for control, P for patients, T for Time-point, here for two controls and 2 patients and for Time point 1).
C1T1 1 0
C2T1 1 0
P1T1 0 1
P2T1 0 1
Contrast: [1 -1]
No need to exchange blocks?
Thanks again,
Have a nice day,
Alexia
Threaded View
Title | Author | Date |
---|---|---|
Alexia Bourgeois | Dec 14, 2017 | |
Leonardo Tozzi | Nov 19, 2019 | |
Leonardo Tozzi | Nov 18, 2019 | |
Andrew Zalesky | Nov 18, 2019 | |
Andrew Zalesky | Dec 16, 2017 | |
Alexia Bourgeois | Dec 19, 2017 | |
Andrew Zalesky | Dec 20, 2017 | |