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help > RE: 2x2 mix effect ANOVA
Dec 6, 2018 05:12 AM | Andrew Zalesky
RE: 2x2 mix effect ANOVA
Hi Thomas,
A within-subject t-test would be sufficient, if you are only interested in the time difference between the two time points in the control group.
The design matrix for three subjects would be:
C1T1 0 1 0 0
C1T2 1 1 0 0
C2T1 0 0 1 0
C2T2 1 0 1 0
C3T1 0 0 0 1
C3T3 1 0 0 1
The contrast would be:
[1 0 0 0] or [-1 0 0 0]
Select: t-test
The exchange blocks would be:
[1 1 2 2 3 3]
Andrew
Originally posted by Thomas Tan:
A within-subject t-test would be sufficient, if you are only interested in the time difference between the two time points in the control group.
The design matrix for three subjects would be:
C1T1 0 1 0 0
C1T2 1 1 0 0
C2T1 0 0 1 0
C2T2 1 0 1 0
C3T1 0 0 0 1
C3T3 1 0 0 1
The contrast would be:
[1 0 0 0] or [-1 0 0 0]
Select: t-test
The exchange blocks would be:
[1 1 2 2 3 3]
Andrew
Originally posted by Thomas Tan:
Hi
Andrew,
Sorry for the confusion when i said CT1T1, i meant control from phase 1, and T2 is phase 2
Therefore, if i am interested only in testing for a difference between the two time points only in the control group, my DM, contrast and exchange block should be looking like this?
Hi Thomas,
I'm not sure what you mean by "CT1T1".
If you are simply interested in testing for a difference between the two time points only in the control group, then the patient data can be omitted and you can do a t-test (repeated measures) only using the control data.
You could then perform the same test for the patient group.
Andrew
Originally posted by Thomas Tan:
Sorry for the confusion when i said CT1T1, i meant control from phase 1, and T2 is phase 2
Therefore, if i am interested only in testing for a difference between the two time points only in the control group, my DM, contrast and exchange block should be looking like this?
Hi Thomas,
I'm not sure what you mean by "CT1T1".
If you are simply interested in testing for a difference between the two time points only in the control group, then the patient data can be omitted and you can do a t-test (repeated measures) only using the control data.
You could then perform the same test for the patient group.
Andrew
Originally posted by Thomas Tan:
Thank you,
If my hypothesis 1 is that the connectivity would be the same in control group (CT1 = CT2), and my hypothesis 2 is that (PT1 = PT2), would i perform t-test separately in each cases? Can you elaborate on this
1. Hypothesis 1 ( CT1T1 = C1T2 )
CT1T1 1 1 0 0 0
CT1T2 0 1 0 0 0
CT2T1 1 0 1 0 0
CT2T2 0 0 1 0 0
contrast [1,0,0,0] or [-1,0,0,0]
If my hypothesis 1 is that the connectivity would be the same in control group (CT1 = CT2), and my hypothesis 2 is that (PT1 = PT2), would i perform t-test separately in each cases? Can you elaborate on this
1. Hypothesis 1 ( CT1T1 = C1T2 )
CT1T1 1 1 0 0 0
CT1T2 0 1 0 0 0
CT2T1 1 0 1 0 0
CT2T2 0 0 1 0 0
contrast [1,0,0,0] or [-1,0,0,0]
Threaded View
| Title | Author | Date |
|---|---|---|
| Thomas Tan | Nov 23, 2018 | |
| Andrew Zalesky | Nov 23, 2018 | |
| Thomas Tan | Nov 26, 2018 | |
| Andrew Zalesky | Nov 27, 2018 | |
| Thomas Tan | Nov 30, 2018 | |
| Andrew Zalesky | Nov 30, 2018 | |
| Thomas Tan | Dec 5, 2018 | |
| Andrew Zalesky | Dec 6, 2018 | |
| Thomas Tan | Dec 11, 2018 | |