users > RE: Registration of 32-bit stacks
Aug 1, 2020  05:08 PM | Greg Jefferis
RE: Registration of 32-bit stacks
Can you show your command and all the output? You can include the -v (verbose) switch 

reformatx -v --outputtype "uint" --pv --floating mylabels.nrrd -o template_labels.nrrd template.nrrd registration.list

to produce additional output.
Originally posted by Francesco Vanzi:
Does it matter if the registration was done on 16bit template and sample?

No it does not matter.

I mean, is it ok if I have my greyscale stack (16 bit), I register that onto a template (16 bit) and then I reformat my labels (32 bit) with the transformation obtained in the registration of those two?

Yes that is fine.
Also, another question to try to better understand the process: my understanding is that the .list folder contains the matrix/ces necessary to reformat the sample into the template space, correct? When I apply this matrix to my labels I should transform them into the template space as well. Why is the template stack needed in the reformat routine?

Yes, your understanding is correct. The template image is needed at this step *only* to specify the dimensions of the new output image, not the transform. It is actually possible to specify these dimensions on the command line, but we recommend doing it this way.

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TitleAuthorDate
Francesco Vanzi Jul 31, 2020
Francesco Vanzi Aug 1, 2020
Greg Jefferis Jul 31, 2020
Francesco Vanzi Jul 31, 2020
Greg Jefferis Jul 31, 2020
Francesco Vanzi Jul 31, 2020
Greg Jefferis Jul 31, 2020
Francesco Vanzi Jul 31, 2020
Greg Jefferis Aug 1, 2020
Francesco Vanzi Aug 1, 2020
Greg Jefferis Aug 1, 2020
Greg Jefferis Aug 1, 2020
Francesco Vanzi Aug 1, 2020
RE: Registration of 32-bit stacks
Greg Jefferis Aug 1, 2020
Francesco Vanzi Aug 1, 2020
Greg Jefferis Aug 1, 2020
Francesco Vanzi Aug 7, 2020