Hi Alfonso,

Thanks for the very helpful response. Just to clarify, In terms of the equation: 2*spm_invTcdf(.95,N-1)*std(x)/sqrt(N), which computes the CIs, does this compute 90% or 95% CIs? Also, when I input these CI values into a plot to produce error bars, the error bars appeared much larger than those that were produced with the CONN toolbox. Do I need to first divide these values by 2 if I want to display the error bars on both sides (both positive and negative) of the average contrast estimates?

Thanks!